Optimal. Leaf size=108 \[ \frac{\left (a^2-a b+b^2\right ) \sin (e+f x)}{a^3 f}-\frac{b^3 \tanh ^{-1}\left (\frac{\sqrt{a} \sin (e+f x)}{\sqrt{a+b}}\right )}{a^{7/2} f \sqrt{a+b}}-\frac{(2 a-b) \sin ^3(e+f x)}{3 a^2 f}+\frac{\sin ^5(e+f x)}{5 a f} \]
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Rubi [A] time = 0.102014, antiderivative size = 108, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.13, Rules used = {4147, 390, 208} \[ \frac{\left (a^2-a b+b^2\right ) \sin (e+f x)}{a^3 f}-\frac{b^3 \tanh ^{-1}\left (\frac{\sqrt{a} \sin (e+f x)}{\sqrt{a+b}}\right )}{a^{7/2} f \sqrt{a+b}}-\frac{(2 a-b) \sin ^3(e+f x)}{3 a^2 f}+\frac{\sin ^5(e+f x)}{5 a f} \]
Antiderivative was successfully verified.
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Rule 4147
Rule 390
Rule 208
Rubi steps
\begin{align*} \int \frac{\cos ^5(e+f x)}{a+b \sec ^2(e+f x)} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (1-x^2\right )^3}{a+b-a x^2} \, dx,x,\sin (e+f x)\right )}{f}\\ &=\frac{\operatorname{Subst}\left (\int \left (\frac{a^2-a b+b^2}{a^3}-\frac{(2 a-b) x^2}{a^2}+\frac{x^4}{a}-\frac{b^3}{a^3 \left (a+b-a x^2\right )}\right ) \, dx,x,\sin (e+f x)\right )}{f}\\ &=\frac{\left (a^2-a b+b^2\right ) \sin (e+f x)}{a^3 f}-\frac{(2 a-b) \sin ^3(e+f x)}{3 a^2 f}+\frac{\sin ^5(e+f x)}{5 a f}-\frac{b^3 \operatorname{Subst}\left (\int \frac{1}{a+b-a x^2} \, dx,x,\sin (e+f x)\right )}{a^3 f}\\ &=-\frac{b^3 \tanh ^{-1}\left (\frac{\sqrt{a} \sin (e+f x)}{\sqrt{a+b}}\right )}{a^{7/2} \sqrt{a+b} f}+\frac{\left (a^2-a b+b^2\right ) \sin (e+f x)}{a^3 f}-\frac{(2 a-b) \sin ^3(e+f x)}{3 a^2 f}+\frac{\sin ^5(e+f x)}{5 a f}\\ \end{align*}
Mathematica [A] time = 0.725452, size = 136, normalized size = 1.26 \[ \frac{30 \sqrt{a} \left (5 a^2-6 a b+8 b^2\right ) \sin (e+f x)+5 a^{3/2} (5 a-4 b) \sin (3 (e+f x))+3 a^{5/2} \sin (5 (e+f x))+\frac{120 b^3 \left (\log \left (\sqrt{a+b}-\sqrt{a} \sin (e+f x)\right )-\log \left (\sqrt{a+b}+\sqrt{a} \sin (e+f x)\right )\right )}{\sqrt{a+b}}}{240 a^{7/2} f} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.089, size = 110, normalized size = 1. \begin{align*}{\frac{1}{f} \left ({\frac{1}{{a}^{3}} \left ({\frac{ \left ( \sin \left ( fx+e \right ) \right ) ^{5}{a}^{2}}{5}}-{\frac{2\, \left ( \sin \left ( fx+e \right ) \right ) ^{3}{a}^{2}}{3}}+{\frac{ \left ( \sin \left ( fx+e \right ) \right ) ^{3}ab}{3}}+{a}^{2}\sin \left ( fx+e \right ) -ab\sin \left ( fx+e \right ) +{b}^{2}\sin \left ( fx+e \right ) \right ) }-{\frac{{b}^{3}}{{a}^{3}}{\it Artanh} \left ({\sin \left ( fx+e \right ) a{\frac{1}{\sqrt{ \left ( a+b \right ) a}}}} \right ){\frac{1}{\sqrt{ \left ( a+b \right ) a}}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.573552, size = 689, normalized size = 6.38 \begin{align*} \left [\frac{15 \, \sqrt{a^{2} + a b} b^{3} \log \left (-\frac{a \cos \left (f x + e\right )^{2} + 2 \, \sqrt{a^{2} + a b} \sin \left (f x + e\right ) - 2 \, a - b}{a \cos \left (f x + e\right )^{2} + b}\right ) + 2 \,{\left (3 \,{\left (a^{4} + a^{3} b\right )} \cos \left (f x + e\right )^{4} + 8 \, a^{4} - 2 \, a^{3} b + 5 \, a^{2} b^{2} + 15 \, a b^{3} +{\left (4 \, a^{4} - a^{3} b - 5 \, a^{2} b^{2}\right )} \cos \left (f x + e\right )^{2}\right )} \sin \left (f x + e\right )}{30 \,{\left (a^{5} + a^{4} b\right )} f}, \frac{15 \, \sqrt{-a^{2} - a b} b^{3} \arctan \left (\frac{\sqrt{-a^{2} - a b} \sin \left (f x + e\right )}{a + b}\right ) +{\left (3 \,{\left (a^{4} + a^{3} b\right )} \cos \left (f x + e\right )^{4} + 8 \, a^{4} - 2 \, a^{3} b + 5 \, a^{2} b^{2} + 15 \, a b^{3} +{\left (4 \, a^{4} - a^{3} b - 5 \, a^{2} b^{2}\right )} \cos \left (f x + e\right )^{2}\right )} \sin \left (f x + e\right )}{15 \,{\left (a^{5} + a^{4} b\right )} f}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.237, size = 184, normalized size = 1.7 \begin{align*} \frac{\frac{15 \, b^{3} \arctan \left (\frac{a \sin \left (f x + e\right )}{\sqrt{-a^{2} - a b}}\right )}{\sqrt{-a^{2} - a b} a^{3}} + \frac{3 \, a^{4} \sin \left (f x + e\right )^{5} - 10 \, a^{4} \sin \left (f x + e\right )^{3} + 5 \, a^{3} b \sin \left (f x + e\right )^{3} + 15 \, a^{4} \sin \left (f x + e\right ) - 15 \, a^{3} b \sin \left (f x + e\right ) + 15 \, a^{2} b^{2} \sin \left (f x + e\right )}{a^{5}}}{15 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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